2y^2-12=y^2+13

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Solution for 2y^2-12=y^2+13 equation:


Simplifying
2y2 + -12 = y2 + 13

Reorder the terms:
-12 + 2y2 = y2 + 13

Reorder the terms:
-12 + 2y2 = 13 + y2

Solving
-12 + 2y2 = 13 + y2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y2' to each side of the equation.
-12 + 2y2 + -1y2 = 13 + y2 + -1y2

Combine like terms: 2y2 + -1y2 = 1y2
-12 + 1y2 = 13 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-12 + 1y2 = 13 + 0
-12 + 1y2 = 13

Add '12' to each side of the equation.
-12 + 12 + 1y2 = 13 + 12

Combine like terms: -12 + 12 = 0
0 + 1y2 = 13 + 12
1y2 = 13 + 12

Combine like terms: 13 + 12 = 25
1y2 = 25

Divide each side by '1'.
y2 = 25

Simplifying
y2 = 25

Take the square root of each side:
y = {-5, 5}

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